Hi All,
I have been working on a yard diagram which has a main frame and a number of ground frames which are unlocked by a key from the main frame. This layout in total will be a 60 lever design with 14 unused levers to space out the ground frames.
Now, I appreciate that SigScribe4 is not capable through the UI of doing the interlocking I need yet, so I thought that this is a situation for using an ITF file. When I try to load the ITF it complains about my second "white" lever being locked in the normal position and stops the processing of my interlocking rules. I tried a few changes to the ITF before stopping and starting a very basic test diagram of what I am trying to do.
The test diagram diagram has a single set of points which have an enabled FPL on them to simulate my larger more complex design. I am working with a 6 lever frame with the levers configured as follows:
1 - White / Unused.
2 - Blue / Simulating the key release in the signal box, not connected to anything on the diagram.
3 - White / Unused.
4 - Blue / FPL connected to the points.
5 - Black / Connected to the points.
6 - White / Unused.
This in my mind is simple. If lever 2 is pulled (ie, I have pulled the lever and taken a key from the locks on it) I am able to release my ground frame by using the key obtained from the signal box (lever 2) and pulling lever 4, which allows me to manipulate the points as controlled by lever 5.
(for clarity, pulled means the lever is in the reverse position also referred to as the position closest to the signaler)
The contents of the ITF for my test frame is:
6
2R:4N,5N
4N:2R
5N:4R
5R:4R
Now, when I load up the ITF into my test diagram, it produces an error stating that Lever 3 is locked in the normal position and again stops processing the rules.
I am sure it is some silly little thing I have wrong but I cannot see it. Any insight or suggestions would be appreciated.
Cheers,
Brian.
Interlocking Table File Problem.
Moderator: RedFred
Brian,
The lever that is locked is in fact the lever with index 3 (counting from 0) which is lever number 4. (I know - it's an intended change!)
To specify both ways locking (as for FPLs), you use B rather than trying to define an R and N condition separately.
This ITF does what you require:
6
2R:4N,5N
4R:5B
The lever that is locked is in fact the lever with index 3 (counting from 0) which is lever number 4. (I know - it's an intended change!)
To specify both ways locking (as for FPLs), you use B rather than trying to define an R and N condition separately.
This ITF does what you require:
6
2R:4N,5N
4R:5B
All the best from "modadmin"
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